Well, if you are asking with respect to the energy levels in the wind, you will have to use the formula Kinectic Energy(K.E.)=0.5 m v^2.

The energy exerted by the wind at 140MPH/225.30816KMPH will be 25381.8824mN, where m represents the mass of the air particle moving, and N being the unit of energy.

Assuming that the same air particle is now moving at 100MPH/160.9344KMPH, the energy exerted by the wind will be 12949.9405mN.

Taking into account that the m in both scenarios are the same, the wind at 140MPH is 1.959999924 times stronger that the wind at 100MPH